Hello Uwe, you could try this:
select * from my_lines l join my_polys p on l.my_line_attribute like '%' + p.my_poly_attribute + '%' Best regard Michael Von: Qgis-user <qgis-user-boun...@lists.osgeo.org> Im Auftrag von Uwe Fischer via Qgis-user Gesendet: Montag, 24. Oktober 2022 13:52 An: qgis-user@lists.osgeo.org Betreff: [Qgis-user] query for Virtual Layer in relation to another layer ACHTUNG!! Diese E-Mail erreicht Sie von einem Absender außerhalb der niedersächsischen Landesverwaltungs-Infrastruktur mit TLS-Verschlüsselung. Bitte klicken Sie auf keine Links oder öffnen Sie keine E-Mail-Anhänge, falls Sie den Absender nicht kennen und nicht wissen, ob der Inhalt sicher ist. Hello, I am looking for a way to create a virtual layer in 3.24 in a 'special' way. I have a line layer with attributes like: xxxx_123_xxxxxxxxx oooo_abc_000_123_0 and a polygon layer with attributes like: abc 123 Now, I would like to use only lines that contain one of the strings that are present in the polygon layer. A prototype for the SQL query might be: select * from my_lines where my_line_attribute in (select my_poly_attribute from my_polys) The problem is that I cannot use the IN clause because the line attributes contain additional surrounding characters around the polygon attributes. The surrounding characters can be any token, so it is not possible to remove them in a systematic way prior to the query. I thought about working with '%123%'. But how do I put every possible value in my_poly_attribute in that clause? That is, '%123%' would have to be in the query as well as '%abc%' Thanks a lot for ideas! Regards, Uwe
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