Hi Gabriel, Does the result change if you first create a Python variable for storing your new layer? I mean:
*referenceSource = create_scratch_reference_layer()* *snapper = QgsGeometrySnapper(referenceSource)* instead of: *snapper = QgsGeometrySnapper(* * referenceSource=create_scratch_reference_layer()* *)* Regards, Germán El jue, 19 oct 2023 a las 14:46, Gabriel De Luca via QGIS-Developer (< qgis-developer@lists.osgeo.org>) escribió: > Hello all, > > I am working with the QgsGeometrySnapper pyqgis class, and have a > problem to snap to a reference layer which is created inside a function > (and returned by it). > > The code shared at [1] prints: > > result = <QgsGeometry: Polygon ((0.10000000000000001 -0.10000000000000001, > 10.09999999999999964 0, 9.90000000000000036 10.09999999999999964, 0 10, > 0.10000000000000001 -0.10000000000000001))> > > Which means that the geomPolygon was not snapped to the reference layer. > But, if uncomment the line 41, which adds the reference layer to the > project, the code prints: > > result = <QgsGeometry: Polygon ((0 0, 10 0, 10 10, 0 10, 0 0))> > > So, for some reason, adding the reference layer to the project makes the > snapper to work. > > I want to ask you if you know why is this happening. Maybe I need to add > something to make it work consistently. > > > Regards, > Gabriel > > [1] https://pastebin.com/raw/Y9v51ZMq > _______________________________________________ > QGIS-Developer mailing list > QGIS-Developer@lists.osgeo.org > List info: https://lists.osgeo.org/mailman/listinfo/qgis-developer > Unsubscribe: https://lists.osgeo.org/mailman/listinfo/qgis-developer > -- ----------- |\__ (:>__)( |/ Soluciones Geoinformáticas Libres http://geotux.tuxfamily.org/ https://twitter.com/GeoTux2 <http://twitter.com/GeoTux2> <http://gis.stackexchange.com/users/4972/germ%c3%a1n-carrillo>
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