Hi Gabriele, WGS84 is not a projection, it's an ellipsoid - a mathematical model of the Earth. You are probably talking about the so-called "Plate carrée" projection where latitudes and longitudes are mapped as X and Y values. And this is a complicated thing because dX is different from dY (meridians are ellipses and parallels are circles).
I would suggest contacting a consultant who is specialized in this area to point you in the right direction for your custom need. I can recommend my colleague Dražen Tutić, he is a professional in this area and did a lot of programming in the context of mapping and projections. You can see some of his work on https://www.north2south.eu/map-projections-and-coordinate-reference-systems/ You can contact him via: Linkedin: http://www.linkedin.com/in/drazen-tutic-0975574 Email: i...@north2south.eu sub, 1. srp 2023. u 19:01 Gabriele Ascolese via QGIS-Developer < qgis-developer@lists.osgeo.org> napisao je: > Hy all, > > i'm developing a c++ gis using qgis api. I have a project in wgs84 > projection. > > I need to draw a complex poligon, so i need to find how is the pixel > resolution per meters, so i can find how many pixel are in 1 meters and use > this value to draw at real dimension. > > How can i find the pixel per meter resolution using QGIS ? I see that > WGS84 projection use degrees as measure unit..but i need meter. > > > > Thank you > _______________________________________________ > QGIS-Developer mailing list > QGIS-Developer@lists.osgeo.org > List info: https://lists.osgeo.org/mailman/listinfo/qgis-developer > Unsubscribe: https://lists.osgeo.org/mailman/listinfo/qgis-developer > -- Srdačan pozdrav / Kind regards, Vedran Stojnović.
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