Thanks Alessandro :-)
(I need some new reading glasses, or maybe a new brain. When you read
the /Properties/ -> /Information/ tab for the layer, the needed
information is shown in the tab with the prefix /*Source*: /! It
shouldn't be that hard for me to guess!!)
Med venlig hilsen / Kind regards
Bo Victor Thomsen
Den 29-04-2021 kl. 14:32 skrev Alessandro Pasotti:
Hi Bo,
iface.activeLayer().source() should give you what you want.
On Thu, Apr 29, 2021 at 2:21 PM Bo Victor Thomsen
<[email protected] <mailto:[email protected]>> wrote:
Hi list -
I have a (probably totally obvious, stupid) Pyhton question:
I need the datasource URI string of a maplayer chosen by the user.
I have found the QgsMapLayer chosen by the user. And the
QgsVectorLayer
associated with the Maplayer.
How do I find the datasource string associated with the
QgsVectorLayer?
There is oodles of QGIS information about generating a vector
layer from
a specific datasource. I need the opposite to generate a virtual
layer
in Python using a join between the chosen layer with a another
predefined layer (which I have the datasource string for).
--
Med venlig hilsen / Kind regards
Bo Victor Thomsen
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--
Alessandro Pasotti
QCooperative: www.qcooperative.net <https://www.qcooperative.net>
ItOpen: www.itopen.it <http://www.itopen.it>
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