Trying to interact with a stopped guest will queue up the events,
then send them all at once when the guest continues running, with
a high chance to have them cause unwanted actions.
Avoid that by only injecting the input events only when the guest
is in running state.
Signed-off-by: Gerd Hoffmann <kra...@redhat.com>
---
input.c | 6 ++++++
1 files changed, 6 insertions(+), 0 deletions(-)
diff --git a/input.c b/input.c
index 9ade63f..b48408d 100644
--- a/input.c
+++ b/input.c
@@ -130,6 +130,9 @@ void qemu_remove_led_event_handler(QEMUPutLEDEntry *entry)
void kbd_put_keycode(int keycode)
{
+ if (!runstate_is_running()) {
+ return;
+ }
if (qemu_put_kbd_event) {
qemu_put_kbd_event(qemu_put_kbd_event_opaque, keycode);
}
@@ -151,6 +154,9 @@ void kbd_mouse_event(int dx, int dy, int dz, int
buttons_state)
void *mouse_event_opaque;
int width, height;
+ if (!runstate_is_running()) {
+ return;
+ }
if (QTAILQ_EMPTY(&mouse_handlers)) {
return;
}
--
1.7.1
