In this case there is no need to call pthread_cond_timedwait; the
function is just a trywait and waiting on the condition variable would
always time out.
Based-on: <20220222090507.2028-1-longpe...@huawei.com>
Cc: "Longpeng(Mike)" <longpe...@huawei.com>
Signed-off-by: Paolo Bonzini <pbonz...@redhat.com>
---
util/qemu-thread-posix.c | 8 ++++++--
1 file changed, 6 insertions(+), 2 deletions(-)
diff --git a/util/qemu-thread-posix.c b/util/qemu-thread-posix.c
index f2ce47d36b..89c23f1d64 100644
--- a/util/qemu-thread-posix.c
+++ b/util/qemu-thread-posix.c
@@ -282,8 +282,12 @@ int qemu_sem_timedwait(QemuSemaphore *sem, int ms)
compute_abs_deadline(&ts, ms);
qemu_mutex_lock(&sem->mutex);
while (sem->count == 0) {
- rc = qemu_cond_timedwait_ts(&sem->cond, &sem->mutex, &ts,
- __FILE__, __LINE__);
+ if (ms == 0) {
+ rc = false;
+ } else {
+ rc = qemu_cond_timedwait_ts(&sem->cond, &sem->mutex, &ts,
+ __FILE__, __LINE__);
+ }
if (!rc) { /* timeout */
break;
}
--
2.34.1
