On 6/5/20 12:00 PM, Joseph Myers wrote:
> The floatx80 remainder implementation sometimes returns the numerator
> unchanged when the denominator is sufficiently larger than the
> numerator. But if the value to be returned unchanged is a
> pseudo-denormal, that is incorrect. Fix it to normalize the numerator
> in that case.
>
> Signed-off-by: Joseph Myers <jos...@codesourcery.com>
> + if (aExp == 0 && aSig0 >> 63) {
> + /* Pseudo-denormal argument must be returned in normalized
> + * form. */
> + return packFloatx80(aSign, 1, aSig0);
We're now standardizing on
/*
* muli-line
* comment
*/
Otherwise,
Reviewed-by: Richard Henderson <richard.hender...@linaro.org>
r~
