Le 03/10/2019 à 09:17, maozy a écrit :
> Hi, Laurent
>
> On 10/1/19 11:46 PM, Laurent Vivier wrote:
>> Le 11/09/2019 à 05:31, Mao Zhongyi a écrit :
>>> if stress function always return 0, the path
>>> 'if (stress(ramsizeGB, ncpus) < 0)' is nerver unreachable,
>>> so fix it to allow the test failed.
>>>
>>> Cc: arm...@redhat.com
>>> Cc: laur...@vivier.eu
>>> Cc: tony.ngu...@bt.com
>>>
>>> Signed-off-by: Mao Zhongyi <maozhon...@cmss.chinamobile.com>
>>> ---
>>> tests/migration/stress.c | 5 ++---
>>> 1 file changed, 2 insertions(+), 3 deletions(-)
>>>
>>> diff --git a/tests/migration/stress.c b/tests/migration/stress.c
>>> index 19a6eff5fd..35903d90c4 100644
>>> --- a/tests/migration/stress.c
>>> +++ b/tests/migration/stress.c
>>> @@ -224,6 +224,7 @@ static int stressone(unsigned long long ramsizeMB)
>>> }
>>> }
>>> }
>>> + return 0;
>>> }
>> before the return, we have an infinite loop "while(1) { }".
>>
>> So this part is dead code.
>>
>> In fact, if the function exits, it's because it fails, otherwise it
>> loops infinitely, so I think we should change its type to void and
>> stress should always return -1.
> Yes, I think it's ok to change stressone typo to void because
> no one cares about its return value, but if make stress always
> return -1, main will always exited in exit_failure, like this:
>
> ...
> if (stress(ramsizeGB, ncpus) < 0)
> exit_failure();
>
> exit_success();
> }
>
> so, perhaps also change stress typo to void may be good. then:
>
> ...
> stress(ramsizeGB, ncpus);
>
> exit_success();
> }
>
> Anther way , make stressone return 0 when infinite loop fails to
> exit, then main can handle both success and failure case.
>
> what do you think?
>
If stressone() or stress() exits it's because of a failure because the
test runs forever otherwise.
So I think there is no problem to use exit_failure() as the exit
function of main(): it should never be reached if the test runs without
error.
Thanks,
Laurent
