Public bug reported:
Running this code:
void (*func)() = 0x12345678;
int main()
{
func();
return 0;
}
Produces the following output:
qemu-arm-static: /build/qemu-DqynNa/qemu-2.8+dfsg/translate-all.c:175: tb_lock:
Assertion `!have_tb_lock' failed.
qemu-arm-static: /build/qemu-DqynNa/qemu-2.8+dfsg/translate-all.c:175: tb_lock:
Assertion `!have_tb_lock' failed.
Segmentation fault
The expected result is as follows:
qemu: uncaught target signal 11 (Segmentation fault) - core dumped
Segmentation fault
** Affects: qemu
Importance: Undecided
Status: New
** Tags: crash usermode
** Attachment added: "qemu-bug.c"
https://bugs.launchpad.net/bugs/1812861/+attachment/5231469/+files/qemu-bug.c
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https://bugs.launchpad.net/bugs/1812861
Title:
QEMU in user-mode emulation mode crashes when the user program jumps
to an invalid address
Status in QEMU:
New
Bug description:
Running this code:
void (*func)() = 0x12345678;
int main()
{
func();
return 0;
}
Produces the following output:
qemu-arm-static: /build/qemu-DqynNa/qemu-2.8+dfsg/translate-all.c:175:
tb_lock: Assertion `!have_tb_lock' failed.
qemu-arm-static: /build/qemu-DqynNa/qemu-2.8+dfsg/translate-all.c:175:
tb_lock: Assertion `!have_tb_lock' failed.
Segmentation fault
The expected result is as follows:
qemu: uncaught target signal 11 (Segmentation fault) - core dumped
Segmentation fault
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