On Tue 09 Feb 2016 11:32:20 AM CET, Kevin Wolf <kw...@redhat.com> wrote:
>> When x-blockdev-del is performed on a BlockBackend that has inserted
>> media it will only succeed if the BDS doesn't have any additional
>> references.
>>
>> The only problem with this is that if the BDS was created separately
>> using blockdev-add then the backend won't be able to be destroyed
>> unless the BDS is ejected first. This is an unnecessary restriction.
>>
>> Now that we have a list of monitor-owned BDSs we can allow
>> x-blockdev-del to work in this scenario if the BDS has exactly one
>> extra reference and that reference is from the monitor.
>>
>> Signed-off-by: Alberto Garcia <be...@igalia.com>
>
> This means that what you created with two blockdev-add commands would be
> destroyed with a single blockdev-del command. I think we all agreed that
> blockdev-add and blockdev-del should always come in pairs.
No, no. I think you are misunderstanding the use case.
Consider this example (testAttachMedia() from iotest 139):
1) blockdev-add creates 'drive0' with a BDS called 'node0'
2) 'node0' is removed from 'drive0' (and therefore destroyed)
3) 'node1' is added using blockdev-add
4) 'node1' is inserted into 'drive0'
Now we want to destroy both 'drive0' and 'node1'. With the current code
we can only do it like this:
5) 'node1' is removed from 'drive0', but not destroyed because it still
has the monitor reference.
6) 'drive0' is destroyed with x-blockdev-del
7) 'node1' is destroyed with x-blockdev-del
The order of 6) and 7) can be changed without problems. However, 5) is
necessary because otherwise 'x-blockdev-del drive0' won't work ('node1'
has 2 references at that point).
I claim that step 5) should be unnecessary.
If we can guarantee that 'node1' has only two references: the one held
by 'drive0' and the monitor reference, then it should be possible to do
'x-blockdev-del drive0' when 'node1' is inserted.
This would destroy 'drive0' but 'node1' would still remain because of
its monitor reference. Now we can do 'x-blockdev-del node1' and complete
the operation.
Berto
