Although not technically not required by POSIX, the writev system call will typically write out its buffers individually. That is, if the first buffer is written successfully, but the second buffer pointer is invalid, then the first chuck will be written and its size is returned.
Signed-off-by: Tom Musta <tommu...@gmail.com> diff --git a/linux-user/syscall.c b/linux-user/syscall.c index fea54be..19e78dc 100644 --- a/linux-user/syscall.c +++ b/linux-user/syscall.c @@ -1798,6 +1798,7 @@ static struct iovec *lock_iovec(int type, abi_ulong target_addr, abi_ulong total_len, max_len; int i; int err = 0; + int bad_address = 0; if (count == 0) { errno = 0; @@ -1838,9 +1839,20 @@ static struct iovec *lock_iovec(int type, abi_ulong target_addr, vec[i].iov_base = 0; } else { vec[i].iov_base = lock_user(type, base, len, copy); + /* If the first buffer pointer is bad, this is a fault. But + * subsequent bad buffers will result in a partial write; this + * is realized by filling the vector with null pointers and + * zero lengths. */ if (!vec[i].iov_base) { - err = EFAULT; - goto fail; + if (i == 0) { + err = EFAULT; + goto fail; + } else { + bad_address = 1; + } + } + if (bad_address) { + len = 0; } if (len > max_len - total_len) { len = max_len - total_len; -- 1.7.1