Il 21/08/2013 03:22, Wanlong Gao ha scritto: > On 08/20/2013 09:43 PM, Paolo Bonzini wrote: >> Il 20/08/2013 03:07, Wanlong Gao ha scritto: >>> -numa node,nodeid=0,cpus=0, \ >>> -numa mem,size=1024M,policy=membind,host-nodes=0-1 \ >>> -numa node,nodeid=1,cpus=1 \ >>> -numa mem,size=1024M,policy=interleave,host-nodes=1 >> >> What nodes would the memory be in, for this command line? Does it just > > The original concept here is that if the nodeid is omitted, it will be > set node by node from node0. Here I also keep the original concept, so the > memory will be in node0 and node1. > >> compute the total and split it evenly across the nodes (so that the >> "-numa node" options could omit nodeid and cpus too)? > > If no memory size is given for any nodes, the memory will split across > all nodes like (ram_size / nb_numa_nodes). And yes nodeid and cpus options > can also be omitted from the original concept. > >> >> Also, do you still need a "-m" option if you use "-numa mem"? > > The "-m" options will be used to compute the memory size of each node > if the memory size of each node is not set by "-numa mem" option. This > is also be consistent with the original concept.
Ok. You didn't answer my exact question though---could you run the above command line without "-m 2048"? (Of course with hotplug like in Igor's case you'll still need "-m maxmem=4096,slots=4" or something like that) Paolo
