On 07/02/13 17:27, Izumi Tsutsui wrote: > Laszlo Ersek wrote: >> Conversely, the only time we need to send a signal is the 0->1 count >> transition (*). > > Per comments from Soda, signals could be required even on count >0, > if more than one threads are sleeping in qemu_cond_timedwait(), > and more than one qemu_sem_post() are called at once, then > the second qemu_sem_post() gets the mutex before sleeping threads > in qemu_sem_timedwait().
You're right. Laszlo
