> >> "The bytes with the register are transmitted in target byte order."
> >>
> >> /* Aliases for Q regs. */
> >> nregs += 16;
> >> if (reg < nregs) {
> >>
> >> - stfq_le_p(buf, env->vfp.regs[(reg - 32) * 2]);
> >> - stfq_le_p(buf + 8, env->vfp.regs[(reg - 32) * 2 + 1]);
> >> + stfq_p(buf, env->vfp.regs[(reg - 32) * 2]);
> >> + stfq_p(buf + 8, env->vfp.regs[(reg - 32) * 2 + 1]);
> >
> > This is wrong. You're still using little-endian ordering of words.
>
> Can you explain a little bit further? If I'm in big-endian mode, stfq_p()
> will be stfq_be_p(), right?
Because we're actually storing two halves of a 128-bit value. You still
store the least significant half first.
Paul
