I'm in "arm user space" with "sigle step mode". I want write "exit\n" in
linux shell (no QEMU monitor) when emulate code arrives to "return 0"
On 06/01/12 14:23, Max Filippov wrote:
On Fri, Jun 1, 2012 at 3:57 PM, Davide Ferraretto
<femudevelopm...@gmail.com> wrote:
I tried to insert " printf("exit\n"); ", but qemu dosen't write to monitor.
printf should not write to monitor (if you mean QEMU monitor), it
should go to stdout.
I don't have ARM compiler set up ATM, but x86_64 with the following
patch does what I describe:
$ git diff
diff --git a/linux-user/syscall.c b/linux-user/syscall.c
index 20d2a74..ccb71dc 100644
--- a/linux-user/syscall.c
+++ b/linux-user/syscall.c
@@ -5052,6 +5052,7 @@ abi_long do_syscall(void *cpu_env, int num, abi_long arg1,
switch(num) {
case TARGET_NR_exit:
+ fprintf(stderr, "TARGET_NR_exit\n");
#ifdef CONFIG_USE_NPTL
/* In old applications this may be used to implement _exit(2).
However in threaded applictions it is used for thread termination,
@@ -6833,6 +6834,7 @@ abi_long do_syscall(void *cpu_env, int num, abi_long arg1,
#ifdef __NR_exit_group
/* new thread calls */
case TARGET_NR_exit_group:
+ fprintf(stderr, "TARGET_NR_exit_group\n");
#ifdef TARGET_GPROF
_mcleanup();
#endif
$ cat a.c
#include<stdio.h>
int main()
{
printf("Hello, world\n");
return 0;
}
$ gcc -static a.c -o a
$ qemu-all/root/bin/qemu-x86_64 ./a
Hello, world
TARGET_NR_exit_group
On 06/01/12 13:43, Max Filippov wrote:
On Fri, Jun 1, 2012 at 3:16 PM, Davide Ferraretto
<femudevelopm...@gmail.com> wrote:
In arm user mode, where does qemu exit? Where is last qemu's instruction?
I.E.
int main (){return 0;}
in what file does qemu run "return 0"??
Simulated code reaches the point where libc calls 'exit' or 'exit_group'
syscall
and then QEMU goes to the do_syscall in the linux-user/syscall.c to
terminate
the process.
