Hello,
On Mon, Jan 22, 2024 at 8:05 PM Peter Maydell <peter.mayd...@linaro.org> wrote:
>
> On Thu, 18 Jan 2024 at 16:03, Manolo de Medici <manolodemed...@gmail.com>
> wrote:
> >
> > Compilation fails on systems where copy_file_range is already defined as a
> > stub.
>
> What do you mean by "stub" here ? If the system headers define
> a prototype for the function, I would have expected the
> meson check to set HAVE_COPY_FILE_RANGE, and then this
> function doesn't get defined at all. That is, the prototype
> mismatch shouldn't matter because if the prototype exists we
> use the libc function, and if it doesn't then we use our version.
Let me answer :)
glibc has this stubs mechanism: a function can be declared in the
system headers, but only implemented as a stub that always fails with
ENOSYS (or some such). You get a linker warning at link time if you
call such a function. For example on GNU/Linux, remove(2) is a stub,
and if I try to use it, the code does compile, but I get
/usr/bin/ld: /tmp/ccLCnRnW.o: in function `main':
demo.c:(.text+0xa): warning: revoke is not implemented and will always fail
during linking. This is done by embedding a
'.gnu.warning.function-name' section inside libc.so (try readelf
--wide --section-headers /lib64/libc.so.6 | grep warning). You can
also find the list of stubs in the gnu/stubs.h header, which contains
definitions like __stub_revoke.
Meson's has_function() knows about this mechanism, and returns false
if the function is declared, but is actually just a stub (by looking
for "__stub_{func}" being defined); autoconf does, too. But as the
prototype is still declared (and the function technically exists, too,
even if it's a stub), you'll get errors if you define the same
function incompatibly yourself.
Sergey
