Il giorno gio 17 feb 2022 alle ore 17:32 Alessandro T.
<[email protected]> ha scritto:
>
> reg = [21070, 12601, 12340, 12593, 12593, 13312]
>
> versione compatta:
> s = ''.join(c for r in reg for i in (1,0) if (c:=chr(r >> 8*i &
> 0xff)).isalnum())
oppure anche
```
>>> "".join(chr(n) for d in reg for n in divmod(d, 256) if n != 0)
'RN190411114'
```
㎝
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