def f( bytes, factor, labels, precision ):
for i, label in enumerate(labels,1):
if (bytes < factor ** i) or (label == labels[-1]):
return '%.*lf %s' % (precision, bytes / factor ** (i-1), label)
Dipende a cosa ti serve. Se รจ solo per 1024 e per i file, quella
di Django va benissimo, ma se devi convertire i millimetri in
Kilometri allora dovresti fotocopiarne un'altra.
On 12/01/2011 13.59, Marcello wrote:
> Massi`,
> pero` il codice qui (cito Nicola, 6a mail di questo thread)
> http://code.djangoproject.com/browser/django/trunk/django/template/defaultfilters.py#L794
> lo trovo piu` leggibile.
> (Esplicito e` meglio che implicito ecc... )
>
> Opinioni personali, eh :)
>
>
> On Wed, Jan 12, 2011 at 1:54 PM, Andrea Ambu<andrea...@gmail.com> wrote:
>> Pythonese
>>
>> def human_from_bytes(bytes, factor=1024., labels=['B', 'KiB', 'MiB', 'GiB',\
>> 'TiB', 'PiB'],
>> precision=2):
>> index = 0
>> while 1. * bytes / factor**index> factor and index< len(labels)-1:
>> index += 1
>> return ('%.*lf %s') % (precision, 1.*bytes/factor**index,
>> labels[index])
>>
>>
>>
>> --
>> Andrea
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>>
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