add a xscrollcommand and/or yscrollcommand keyword argument to the
construction of your listbox.
def func(*a):
print "i'm a callback!"
L = Tkinter.Listbox(root, yscrollcommand=func) # note no parens
after func
groves wrote:
> hi eveyrbody , i have started working on python tkinter,
> While I was working on one of the tkinter classes..named listbox
> widget. I had a slight problem.
>
> Now let me tell you that i was able to create a simple listbox which
> had 6 options which one can select, but Now what I want is that from
> the available menu, if I select an option it should give me another
> menu associated with that option. Its like digging up that option to do
> advance search.
>
> Please I need help as I am making my project
> Thanks to eveyrbody who will take time to read this and solve it .
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