Gerard> David Hirschfield wrote: >> I have this function: >> >> def sequentialChunks(l, stride=1): ... >> >> Which takes a list of numerical values "l" and splits it into chunks >> where each chunk is sequential...
Gerard> see the groupby example here: Gerard> http://docs.python.org/lib/itertools-example.html I've never been a fan of the operator module, so I find the example in the docs ugly even though it's succinct. I'd also never used groupby but thought it was the solution to the problem. As I was walking home from the train I realized how it would work. You beat me to the punch with your reply, but I'll post my solution anyway: from itertools import groupby class Counter: def __init__(self): self.last = None self.value = True def __call__(self, val): if self.last is not None and self.last+1 != val: self.value = not self.value self.last = val return self.value for key, group in groupby([1,2,3, 5,6, 8, 12,13,14], Counter()): print list(group) Skip -- http://mail.python.org/mailman/listinfo/python-list