On 8/07/2006 9:29 AM, tac-tics wrote:
> Python is a crazy language when it comes to object versatility. I know
> I can do:
>
>>>> class test:
> ... def __init__(self):
> ... pass
>>>> x = test()
>>>> def fun():
> ... print "fun"
>>>> x.fun = fun
>>>> x.fun()
> fun
>
> However, experimenting shows that these attached functions are not
> bound to the object. They do not accept the 'self' parameter. I want to
> know how one goes about doing that. How do I bind a function to an
> object to act as if it were a method? It looks like the classmethod()
> built-in looks *similar* to what I want to do, but not quite.
>
> Any help would be awesome =-)
>
Call me crazy, but wasn't this discussed in a thread only a few days ago?
Injecting a method into a class, so that even already-created instances
have that method, is trivial:
>>> class K(object):
... pass
...
>>> def fun(self, arg):
... print "fun"
... self.frob = arg
...
>>> o = K()
>>> K.methc = fun
>>> o.methc("xyz")
fun
>>> o.frob
'xyz'
>>>
Injecting a "private" method into a particular instance is not much more
complicated:
>>> def own(self, arg):
... print "own"
... self.ozz = arg
...
>>> p = K()
>>> import types
>>> p.metho = types.MethodType(own, p)
>>> p.metho("plugh")
own
>>> p.ozz
'plugh'
>>> o = K()
>>> o.metho("xyzzy")
Traceback (most recent call last):
File "<stdin>", line 1, in ?
AttributeError: 'K' object has no attribute 'metho'
>>>
and no __makeyoureyesbleed__ __doubleunderscoremessingabout__ required :-)
Cheers,
John
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