sanjeevdivekar a écrit : > hi, > > i am newbie to python so i am trying to learn mod_python as my new > development kit for my small web apps. > > i am getting strange result
Nothing strange here AFAICT. > can anybody explain me. > index.py > ********************************************************************************************* > from mod_python import apache > from mod_python import psp > from mod_python import util > > def index(req, para=None): > tmpl = psp.PSP(req, filename='a.html') > tmpl.run(vars = {'para':para}) > tmpl.run() Here, you call tmpl.run() two time, the first time with a dict having an entry named 'param', the second time without it. > a.htm > ********************************************************************************************* (snip) > <BODY> > <h1><%=para%></h1> And here you try to display something named "para". I don't have much knowledge of PSP, but I have enough experience to assert this try to get the entry named "param" from the dict passed to tmpl.run(). (snip) > Result (snip) > File "E:\Apache Group\Apache2\htdocs\test\index.py", line 8, in index > tmpl.run() Here we are : line 8 of index.py, your second call to tmpl.run() without the dict. > File "E:\Python24\Lib\site-packages\mod_python\psp.py", line 213, in > run exec code in global_scope > File "E:\Apache Group\Apache2\htdocs\test\a.html", line 1, in ? > NameError: name 'para' is not defined and here the tentative to get this name from the dict. Doesn't seem so strange to me. Note that I could be wrong - you'd better check in PSP documentation - but I think I'd try commenting out the second (and AFAICT useless) call to tmpl.run(). -- http://mail.python.org/mailman/listinfo/python-list