Thomas Nelson wrote:
> This is exactly what I want to do: every time I encounter this kind of
> value in my code, increment the appropriate type by one. Then I'd like
> to go back and find out how many of each type there were. This way
> I've written seems simple enough and effective, but it's very ugly and
> I don't think it's the intended use of lists. Does anyone know a
> cleaner way to have the same funtionality?
>
> Thanks,
> THN
Just assign each type a number (type1 -> 1, type2 -> 2) and then count
the values as usual
def count(map, it):
d={}
for x in it:
x = map[x] #only difference from normal count function
#d[x]=d.get(x,0)+1
if x in d:
d[x] +=1
else:
d[x] = 1
return d
>>> map = {0:1, 1:1, 2:3, 3:1, 4:2}
>>> count(map, [1,1,0,4])
{1: 3, 2: 1}
>>> for x in count(map, [1,1,0,4]).items():
... print 'type%d: %d' %x
...
type1: 3
type2: 1
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