no, its an extern IP adress. For my needs the server and the client
must be on different machines. But I opened the port and it worked.
Thanks anyway :)
Greetz,
Stefka
Marco Aschwanden wrote:
> > server = SimpleXMLRPCServer.SimpleXMLRPCServer(("xxx.xxx.xxx.xxx",
> > 22999))
>
> Could it be that xxx.xxx.xxx.xxx stands for '127.0.0.1'? If so... rename
> it to 'localhost'. If you bind a port to 127.0.0.1 it will be found only
> on the same machine.
> Greetings,
> Marco
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