In <[EMAIL PROTECTED]>, manstey wrote:
> I often have code like this:
>
> data='asdfbasdf'
> find = (('a','f')('s','g'),('x','y'))
> for i in find:
> if i[0] in data:
> data = data.replace(i[0],i[1])
>
> is there a faster way of implementing this? Also, does the if clause
> increase the speed?
It decreases it. You search through `data` in the ``if`` clause. If it's
`False` then you have searched the whole data and skip the replace. If
it's `True` you searched into data until there's a match and the the
`replace()` starts again from the start and searches/replaces through the
whole data.
You can get rid of the indexes and make the code a bit clearer by the way:
for old, new in find:
data = data.replace(old, new)
Ciao,
Marc 'BlackJack' Rintsch
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