I tried what you said and it looked like maybe AttributeError, but that
didn't work either.
This code snippet:
import shelve
from traceback import format_exc
try:
db = shelve.open("meh", "r")
except:
print format_exc()
Gave me this output:
Traceback (most recent call last):
File "test.py", line 5, in ?
db = shelve.open("meh", "r")
File "/usr/lib/python2.4/shelve.py", line 231, in open
return DbfilenameShelf(filename, flag, protocol, writeback, binary)
File "/usr/lib/python2.4/shelve.py", line 212, in __init__
Shelf.__init__(self, anydbm.open(filename, flag), protocol,
writeback, binary)
File "/usr/lib/python2.4/anydbm.py", line 77, in open
raise error, "need 'c' or 'n' flag to open new db"
error: need 'c' or 'n' flag to open new db
Exception exceptions.AttributeError: "DbfilenameShelf instance has no
attribute 'writeback'" in ignored
Do you know what the error is?
Thanks,
Martin
Simon Forman wrote:
> [EMAIL PROTECTED] wrote:
> > I wanted to write the following code:
> >
> > import shelve
> > try:
> > db = shelve.open(file, "r")
> > except SomeError:
> > print "Oh no, db not found"
> >
> > Only, I'm not sure what SomeError should be. I tried error,
> > anydbm.error, shelve.open.anydb.error, etc. but can't find it. Things
> > worked fine with simply except:, but that's not optimal.
> >
> > Does anyone know either the what the error is or where I can find it
> > for certain?
> >
> > Thanks,
> > Martin
>
> What error did you get with just the bare except?
>
> you can find out by saying (for instance):
>
> >>> try:
> 1/0
> except Exception, err:
> E = err
>
>
> >>> E
> <exceptions.ZeroDivisionError instance at 0xb6efd8cc>
>
>
> or to get really fancy, use the traceback module
>
> >>> from traceback import format_exc
> >>> try:
> 1/0
> except:
> print format_exc()
>
>
> Traceback (most recent call last):
> File "<pyshell#10>", line 2, in ?
> ZeroDivisionError: integer division or modulo by zero
>
>
>
> Peace,
> ~Simon
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