Nothing got printed. Could you tell me what would be pythonic version of what I am trying to do?
Diez B. Roggisch wrote: > > p[j] does not give you a reference to an element inside p. It gives > > you a new sublist containing one element from p. You then append a > > column to that sublist. Then, since you do nothing more with that > > sublist, YOU THROW IT AWAY. > > Not correct. > > p = [[]] > p[0].append(1) > print p > > yields > > [[1]] > > p[0] _gives_ you a reference to an object. If it is mutable (list are) and > append mutates it (it does), the code is perfectly alright. > > I don't know what is "not working" for the OP, but actually his code works > if one replaces the csv-reading with a generated list: > > cnt = 0 > p=[[], [], [], [], [], [], [], [], [], [], []] > reader = [["column_%i" % c for c in xrange(5)] for l in xrange(7)] > for line in reader: > if cnt > 6: > break > j = 0 > for col in line: > p[j].append(col) > j=j+1 > cnt = cnt + 1 > print p > > > You are right of course that it is the most unpythonic way imaginabe to do > it. But it works. > > Diez -- http://mail.python.org/mailman/listinfo/python-list
