I woulkdn't interate at the same time. zip takes two lists, and makes a single list of tuples, not the other way around. The easilest solution is feed_list = [ix.url for ix in feeds_list_select] feed_id = [ix.id for ix in feeds_list_select]
Also, a big feature of list comprehension is it filters too... for example high_id_names = [ix.url for ix in feeds_list_select if ix.id > 500] Sometimes list comprehensions just read nicely. a wrote: > hey guys > this is gr8 > but in cheetah > i use > for test in $ix > $test.url > end for > to iterate thru loop > > now how do i iterate feed_list and feed_id along with i, > thanks a lot > > N = [(ix.url, ix.id) for ix in feeds_list_select] > > feed_list, feed_id = zip(*N) > > or just > > feed_list, feed_id = zip(*[(ix.url, ix.id) for ix in > feeds_list_select]) > > Simon Forman wrote: > > a wrote: > > > hi simon thanks for your reply > > > > You're most welcome > > > > > > > what if i want to do this > > > feed_list=[] > > > feed_id=[] > > > for ix in feeds_list_select: > > > global feeds_list > > > global feeds_id > > > feeds_list.append(ix.url) > > > feeds_id.append(ix.id) > > > > > > ie not one variable but more variables > > > thanks > > > > in a case like this I would usually reach for the zip() function, with > > the "varargs" * calling pattern > > > > N = [(ix.url, ix.id) for ix in feeds_list_select] > > > > feed_list, feed_id = zip(*N) > > > > > > or just > > > > feed_list, feed_id = zip(*[(ix.url, ix.id) for ix in > > feeds_list_select]) > > > > > > btw, please note that the global statements in your example are > > unnecessary.. *totally* unnecessary. :-D -- http://mail.python.org/mailman/listinfo/python-list
