Hi All,
I'm having a tough time converting the following regex.compile patterns
into the new re.compile format. There is also a differences in the
regsub.sub() vs. re.sub()
Could anyone lend a hand?
import regsub
import regex
import re # << need conversion to this module
....
"""Convert perl style format symbology to printf tokens.
Take a string and substitute computed printf tokens for perl style
format symbology.
For example:
###.## yields %6.2f
######## yields %8d
<<<<< yields %-5s
"""
exponentPattern = regex.compile('\(^\|[^\\#]\)\(#+\.#+\*\*\*\*\)')
floatPattern = regex.compile('\(^\|[^\\#]\)\(#+\.#+\)')
integerPattern = regex.compile('\(^\|[^\\#]\)\(##+\)')
leftJustifiedStringPattern = regex.compile('\(^\|[^\\<]\)\(<<+\)')
rightJustifiedStringPattern = regex.compile('\(^\|[^\\>]\)\(>>+\)')
while 1: # process all integer fields
print("Testing Integer")
if integerPattern.search(s) < 0: break
print("Integer Match : ", integerPattern.search(s).span() )
# i1 , i2 = integerPattern.regs[2]
i1 , i2 = integerPattern.search(s).span()
width_total = i2 - i1
f = '%'+`width_total`+'d'
# s = regsub.sub(integerPattern, '\\1'+f, s)
s = integerPattern.sub(f, s)
Thanks in advance!
Steve
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