Bruno Desthuilliers wrote:
> placid wrote:
> > Duncan Booth wrote:
> >
> >>placid wrote:
> >>
> >>
> >>>Hi all,
> >>>
> >>>Can someone tell me what * in the following code means/does a Google
> >>>search didnt turn up anything as i dont know what the * is called
> >>>(related to Python and i dont think Python has pointers)
> >>>
> >>
> >>* is for variable number of positional arguments, ** is for variable
> >>keyword arguments. The syntax is symmetrical when defining functions and
> >>when calling them.
> >>
> >>See http://docs.python.org/ref/calls.html
> >>and http://docs.python.org/ref/function.html
> >
> >
> > so * basically means that args is a list
>
> A tuple IIRC
>
> > containing more arguments that
> > can change in size, whereas ** means that args is a dictionary of
> > key=value arguments?
> >
>
> Why don't you try by yourself in the Python shell ? One of the nice
> things with Python is that it's quite easy to explore and experiment.
i did try it in a Python shell after i learnt what it was. Like i said
*args will be a list, but when i try **args with the following code it
doesnt work
def test(**args):
keys = args.keys()
for key in keys:
print key+"="+args(key)
>
>
> --
> bruno desthuilliers
> python -c "print '@'.join(['.'.join([w[::-1] for w in p.split('.')]) for
> p in '[EMAIL PROTECTED]'.split('@')])"
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