>> thanks lawrence...however this func doesnt return the permuted strings,
>> so
>> i added some code as follows to generate a list of all the permutations:
>>
>> def permute(seq):
>> l = []
>> if len(seq) == 0:
>> yield []
>> else:
>> for i in range(0,len(seq)):
>> for rest in permute(seq[:i] + seq[i+1:]):
>> yield (seq[i],) + rest
>> for t in permute(seq):
>> l.append(''.join(t))
>> return l
>>
>> This gives me a syntax error!
>> I need to output a list that has all the permutations of the input
>> string.
>>
>>
>>
>>
>>>--
>>>http://mail.python.org/mailman/listinfo/python-list
>>>
>>
>>
>
> p = ["".join(s) for s in permute('abcdefg')]
This fails to work too. I'm trying to call permute func from another func,
python gives me a TypeError as follows:
def permute(seq):
l = []
if len(seq) == 0:
yield []
else:
for i in range(0,len(seq)):
for rest in permute(seq[:i] + seq[i+1:]):
yield (seq[i],) + rest
def main(stringList):
for string in stringList:
permList = list(permute(string))
l = ["".join(s) for s in permList]
>>> l = ['abc','abd','bcd']
>>> main(l)
TypeError: can only concatenate tuple (not "list") to tuple
>
> --
> James Stroud
> UCLA-DOE Institute for Genomics and Proteomics
> Box 951570
> Los Angeles, CA 90095
>
> http://www.jamesstroud.com/
> --
> http://mail.python.org/mailman/listinfo/python-list
>
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http://mail.python.org/mailman/listinfo/python-list
