> Paolo Pantaleo wrote:
>
>> I have a function
>>
>> def f(the_arg):
>> ...
>>
>> and I want to state that the_arg must be only of a certain type
>> (actually a list). Is there a way to do that?
>
> Yes and no. You can ensure that the passed object is a list, by calling e.g.
>
> def f(arg):
> if not isinstance(arg, list):
> raise "Not a list!"
>
>
> Alternatively, you can just use it as an iterable - and the exception will
> come from arg not being iterable.
>
> But what you can't do is make python complain about this:
>
> def f(arg):
> for e in arg:
> print e
>
>
> f(100)
>
> before actually calling f. It will always fail at runtime.
>
> Diez
What about
def f(arg):
if type(arg)=='list':
#do something
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Rony Steelandt
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