On 20/06/2006 5:55 AM, Rob Cowie wrote:
> Hi all,
>
> Is there a simple way to call every method of an object from its
> __init__()?
>
> For example, given the following class, what would I replace the
> comment line in __init__() with to result in both methods being called?
> I understand that I could just call each method by name but I'm looking
> for a mechanism to avoid this.
>
> class Foo(object):
> def __init__(self):
> #call all methods here
> def test(self):
> print 'The test method'
> def hello(self):
> print 'Hello user'
>
=== question ===
Why? What is the use case for a class *all* of whose methods can be
called blindly from the __init__()?
=== code ===
class Foo(object):
def __init__(self):
#call all methods here
for x in dir(self):
if not x.startswith("__"):
method = getattr(self, x)
if callable(method):
print x, type(method), repr(method)
method()
def test(self):
print 'The test method'
def hello(self):
print 'Hello user'
def variablenumberofargsohbuggerbacktothedrawingboard(self, arg1,
arg2):
print 'The unseen message'
obj = Foo()
=== output ===
hello <type 'instancemethod'> <bound method Foo.hello of <__main__.Foo
object at 0x00AE2B70>>
Hello user
test <type 'instancemethod'> <bound method Foo.test of <__main__.Foo
object at 0x00AE2B70>>
The test method
variablenumberofargsohbuggerbacktothedrawingboard <type
'instancemethod'> <bound method
Foo.variablenumberofargsohbuggerbacktothedrawingboard of <__main__.Foo
object at 0x00AE2B70>>
Traceback (most recent call last):
File "C:\junk\cowie.py", line 17, in ?
obj = Foo()
File "C:\junk\cowie.py", line 9, in __init__
method()
TypeError: variablenumberofargsohbuggerbacktothedrawingboard() takes
exactly 3 arguments (1 given)
Cheers,
John
--
http://mail.python.org/mailman/listinfo/python-list
