Girish Sahani wrote: > > Also,i am getting a ValueError in the code below: > > for s in prunedNew: > substrings = [s[:i]+s[i+1:] for i in range(len(s))] > for string in substrings: > if string not in prunedK: > prunedNew.remove(s) > continue > continue > > The error is: > prunedNew.remove(s) > ValueError: list.remove(x): x not in list > > Could anyone enlighten me as to why i'm getting these two errors??
Why don't you use sets instead of lists ? It would make your life much easier. Specifically here, the problem seems to be that for some s there is more than one substring of it that fails to be in prunedK, so that the failing line is called more than once for a single s. The simplest modification is to replace your first 'continue' by a 'break' (and remove the second 'continue' which serves no purpose). -- http://mail.python.org/mailman/listinfo/python-list
