[EMAIL PROTECTED]:
> I'd like to have a dictionary (actually a nested dictionary) to call
> these functions so I can avoid if-then-elsing everything. Eath
> dictionary item has three things in it: the function to be called, a
> string to pass to the function (which is also the key to the dict), and
> a tuple to pass to the function. In the case of the function with no
> arguments, obviously I'd like not to pass anything.
[...]
> something like this:
> alldict = \
> {'pulse': {'func': self.arbtrandef, 'args':(2,5)},\
> 'sin' : {'func': self.arbtrandef, 'args':(2,3)},\
> 'exp' : {'func': self.arbtrandef, 'args':(2,4)},\
> 'pwl' : {'func': self.pwldef , 'args':
> (None,)},\ <------- how
> do I store "no" arguments?
> 'sffm' : {'func': self.arbtrandef, 'args':(5,0)}}
>
> for it in alldict.items():
> name = it[0]
> args = (name,) + it[1]['args']
> it[1]['func'](*args)
I would do it like this:
alldict = {
'pulse': (self.arbtrandef, (2, 5)), # function and args packed in a tuple
'sin' : (self.arbtrandef, (2, 3)),
'exp' : (self.arbtrandef, (2, 4)),
'pwl' : (self.pwldef, ()), # empty tuple represented by ()
'sffm' : (self.arbtrandef, (5, 0)),
}
for (fname, (func, args)) in alldict.items(): # items unpacked directly
func(fname, *args)
Best regards.
--
Roberto Bonvallet
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