On 2/06/2006 9:08 AM, A.M wrote:
> Hi,
>
> Is there any built in feature in Python that can format long integer
> 123456789 to 12,3456,789 ?
>
> Thank you,
> Alan
Not that I know of, but this little kludge may help:
8<---
import re
subber = re.compile(r'^(-?\d+)(\d{3})').sub
def fmt_thousands(amt, sep):
if amt in ('', '-'):
return ''
repl = r'\1' + sep + r'\2'
while True:
new_amt = subber(repl, amt)
if new_amt == amt:
return amt
amt = new_amt
if __name__ == "__main__":
for prefix in ['', '-']:
for k in range(11):
arg = prefix + "1234567890.1234"[k:]
print "<%s> <%s>" % (arg, fmt_thousands(arg, ","))
8<---
HTH,
John
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