David Isaac wrote: > 2. Is this a good argmax (as long as I know the iterable is finite)? > def argmax(iterable): return max(izip( iterable, count() ))[1]
In Python 2.5: Python 2.5a2 (trunk:46491M, May 27 2006, 14:43:55) [MSC v.1310 32 bit (Intel)] on win32 >>> iterable = [5, 8, 2, 11, 6] >>> import operator >>> max(enumerate(iterable), key=operator.itemgetter(1)) (3, 11) STeVe -- http://mail.python.org/mailman/listinfo/python-list
