Le 01-06-2006, [EMAIL PROTECTED] <[EMAIL PROTECTED]> nous disait: > hi > i have declared a function like this: > > def aFunction ( arg1 , arg2 = 0): > .... > print type(arg2) > > when i try to print the type of arg2, it gives me 'str' type..why is it > not integer type, since i have > declared it as 0 ??
You probably either called the function with a string as the second argument, or assigned a string to arg2 in the ... part of the function. On my box, I get what you would expect: >>> def aFunction ( arg1 , arg2 = 0): ... print type(arg2) ... >>> aFunction(2) <type 'int'> Now, remember that there are no variables in Python, only identifiers, which are refering to values. When you print type(arg2), you are not printing the "type of variable arg2", but the "type of the value referenced by arg2", which is quite different, especially because it can change during the execution of the program. -- Alexandre Fayolle LOGILAB, Paris (France) Formations Python, Zope, Plone, Debian: http://www.logilab.fr/formations Développement logiciel sur mesure: http://www.logilab.fr/services Python et calcul scientifique: http://www.logilab.fr/science -- http://mail.python.org/mailman/listinfo/python-list
