This is the third problem today which I propose to solve with my stream
editor SE. If the group thinks it could be useful I would submit it the
moment I'm done with the doc, which is in the final stage.
Frederic
>>> se = SE.SE ('<EAT> ~addr=[0-9.]+~==(10) | addr\== ')
>>> string = """(a)test="192.168.1.17:/home/ankur/nios_fson/mnt/tmptype
> nfs(rw,addr=192.168.1.17)"
> b)test="/dev/root on / typr nfs
> (rw,v2,rsize=1024,wsize=1024,hard,udp,nolock,addr=192.168.1.93)")""")
>>> print se (string)
192.168.1.17
192.168.1.93
----- Original Message -----
From: "Hari" <[EMAIL PROTECTED]>
Newsgroups: comp.lang.python
To: <python-list@python.org>
Sent: Monday, May 08, 2006 12:18 PM
Subject: How to get a part of string which follows a particular pattern
usingshell script
> Hi all,
>
> I need to get a part of string which follows a pattern 'addr='
>
>
> For example:
>
>
> a)test="192.168.1.17:/home/ankur/nios_fson/mnt/tmptype
> nfs(rw,addr=192.168.1.17)"
> b)test="/dev/root on / typr nfs
> (rw,v2,rsize=1024,wsize=1024,hard,udp,nolock,addr=192.168.1.93)"
>
>
> I need to get the ipaddress from the above two strings a and b which
> follows 'addr='. I tried to use cut, but it accepts only single charter
>
> as delimiter. If I give delimiter as 'addr=' for cut command it gives
> me a error.
>
>
> So please help me.
>
>
> A bunch of thanks in advance.
>
>
> Regards,
> P.R.Hariram
>
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