Hi don,
there may well be a better way then regex, although I find them usefull
and use them a lot.
The way they work would be dependant on knowing some things. For
example, if the dir you are after is always 4
deep in the structure you could try something like...
path =
'/main/parallel_branch_1/release_branch_1.0/dbg_for_python/CHECKEDOUT
from /main/parallel_branch_1/release_branch_1.0/4'
p = re.compile('/\S*/\S*/\S*/(\S*)/')
m = re.search(p, path)
.
if m:
print m.group(1)
This is a good reference...
http://www.amk.ca/python/howto/regex/
Hope that helps,
aaron.
don wrote:
>I have a string from a clearcase cleartool ls command.
>
>/main/parallel_branch_1/release_branch_1.0/dbg_for_python/CHECKEDOUT
>from /main/parallel_branch_1/release_branch_1.0/4
>
>I want to write a regex that gives me the branch the file was
>checkedout on ,in this case - 'dbg_for_python'
>
>Also if there is a better way than using regex, please let me know.
>
>Thanks in advance,
>Don
>
>
>
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