Lawrence Oluyede wrote:
> "[EMAIL PROTECTED]" <[EMAIL PROTECTED]> writes:
>
>
>>However, I wonder why L.sort() don't return the reference L, the
>>performance of return L and None may be the same.
>
>
> It's not "the same". sort() does not return anything.
Yes it does : it returns the None object.
>
>>Why?
>
> I've just explained to you and so the others: by default operations on mutable
> objects are in place.
this is pure non-sens :
class MyList(list):
def sort(self):
return sorted(self)
This is a mutable object, and the sort() is not in place.
class MyObj(object):
def __init__(self, name):
self.name = name
def sayHello(self):
return "hello from %s" self.name
This is another mutable object, and I fail to see how 'in place' could
sensibly have any meaning when applied to sayHello().
Also, and FWIW, the fact that a method modifies the object it's called
on doesn't technically prevent it from returning the object:
class MyOtherList(list):
def sort(self, *args, **kw):
list.sort(self, *args, **kw)
return self
> s = "abc"
> s.upper()
>
> does return another string. String are immutable references.
Strings are immutable *objects*.
--
bruno desthuilliers
python -c "print '@'.join(['.'.join([w[::-1] for w in p.split('.')]) for
p in '[EMAIL PROTECTED]'.split('@')])"
--
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