Fredrik Lundh a écrit :
> Christophe wrote:
>
>
>>That's easy, since A is a symbolic constant know at compile time, and
>>since it's a known mutable objet, the code once compiled will be
>>equivalent to:
>>
>> >>> b = [[]]
>>
>> >>> # much later
>> >>> b|0].append('1')
>
>
> the OP talked about constants as names for immutable objects, not pre-
> processor macros. but alright, using the "symbolic constant" approach,
> what would this print ?
>
> >>> def foo(var):
> ... var.append('1')
> ... print var
> ...
> >>> b = []
> >>> foo(b)
> >>> foo(b)
I think you've made a mistake in your example. This is valid today's
Python you know :) And it'll print more or less :
['1']
['1', '1']
> and this ?
>
> >>> constant A = []
> >>> print A is A
Obviously, False.
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