> If I want to create a list of the form [100, 99, 99, 98, 98, 97, 97...]
> (where each item is repeated twice after the first one), how might I do
> that most efficiently?
>
> Right now I have this:
>
> series = [100]
> for x in range(10): # just for testing
> series.append(series[-1] - 1)
Well, you can do something like
def foo(start):
count = 0
while 1:
yield start - ((count + 1) / 2)
count += 1
which is pretty efficient in the matter. If you just need
the results, you can do something like
series = [100]
for _ in range(10):
series.extend([x[-1]-1]*2)
Both should get you what you want, and one or the other may
be better depending on the scenario in which you want to use it.
-tkc
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