[EMAIL PROTECTED] wrote:
>
> Kun> assuming that my date column is 2, how would i parse out the date?
>
> No parsing required. Just get its date:
>
> d = record[2].date()
>
> The str() of a datetime.date object is a string in YYYY-MM-DD form.
or, in other words, change:
for col in range(0, numcols):
print "<td>", record[col], "</td>"
to
# convert to list, so we can replace columns, if needed
record = list(record)
# fix the date column
record[2] = record[2].date()
# add other fixups here
# print it out
for col in range(0, numcols):
print "<td>", record[col], "</td>"
the last two lines are of course better written as
for col in record:
print "<td>", col, "</td>"
</F>
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