Hi all
Assume a 2-dimensional list called 'table' - conceptually think of it
as rows and columns.
Assume I want to create a temporary copy of a row called 'row',
allowing me to modify the contents of 'row' without modifying the
contents of 'table'.
I used to fall into the newbie trap of 'row = table[23]', but I have
learned my lesson by now - changing 'row' also changes 'table'.
I have found two ways of doing it that seem to work.
1 - row = table[23][:]
2 - row = []
row[:] = table[23]
Are these effectively identical, or is there a subtle distinction which
I should be aware of.
I did some timing tests, and 2 is quite a bit faster if 'row'
pre-exists and I just measure the second statement.
TIA
Frank Millman
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