On Sat, 01 Apr 2006 14:56:02 -0500, Roy Smith wrote:
> I've got a bunch of strings in a list:
>
> vector = []
> vector.append ("foo")
> vector.append ("bar")
> vector.append ("baz")
>
> I want to send all of them out a socket in a single send() call, so
> they end up in a single packet (assuming the MTU is large enough). I
> can do:
>
> mySocket.send ("".join (vector))
>
> but that involves creating an intermediate string. Is there a more
> efficient way, that doesn't involve that extra data copy?
Is sendall() what you're looking for?
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