Em Sáb, 2006-04-01 às 20:44 +1000, Steven D'Aprano escreveu: > Here's another way of doing it: > > lst = [2, 4, 42] > any(map(lambda x: x==42, lst))
In fact, as we're talking about Python 2.5 anyway, it would be better not to waste memory and use: any(x == 42 for x in lst) -- Felipe. -- http://mail.python.org/mailman/listinfo/python-list
