John Salerno wrote: > Ok, I'm stuck on another Python challenge question. Apparently what you > have to do is search through a huge group of characters and find a > single lowercase character that has exactly three uppercase characters > on either side of it. Here's what I have so far: > > pattern = '([a-z][A-Z]{3}[a-z][A-Z]{3}[a-z])+' > print re.search(pattern, mess).groups() > > Not sure if 'groups' is necessary or not. > > Anyway, this returns one matching string, but when I put this letter in > as the solution to the problem, I get a message saying "yes, but there > are more", so assuming this means that there is more than one character > with three caps on either side, is my RE written correctly to find them > all? I didn't have the parentheses or + sign at first, but I added them > to find all the possible matches, but still only one comes up. > > Thanks.
I don't believe you _need_ the parenthesis or the + in that usage... Have a look at http://docs.python.org/lib/node115.html It should be obvious which method you need to use to "find them all" -- - Justin -- http://mail.python.org/mailman/listinfo/python-list