thanks for help. formerly I only know to use the struct like bellow: >>> unpack('hhl', '\x00\x01\x00\x02\x00\x00\x00\x03') Great, python can work like this: >>> l = list(struct.unpack('h'*(len(s)/2), s)) I will try to use the numarray also >>>there are some good exensions for Python, >>>numarray and numpy and so on ... >>>(http://numeric.scipy.org/)
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