Terry That is very succint. Rewriting my shift function given earlier:
>>> import string >>> alpha = string.ascii_lowercase >>> print alpha abcdefghijklmnopqrstuvwxyz >>> def shift(lst, n): return [lst[(i+len(lst)-n)%len(lst)] for i,item in enumerate(lst)] >>> print shift(alpha,2) ['y', 'z', 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x'] Shorter and possibly as clear too; thanks! Keep well Caleb -- http://mail.python.org/mailman/listinfo/python-list